The division algorithm states that if​ p(x) and​ d(x) are polynomial functions with d left parenthesis x right parenthesis not equals 0 comma and the degree of​ d(x) is less than or equal to the degree of​ p(x), then there exist unique polynomial functions​ q(x) and​ r(x) such that

Respuesta :

Answer:

I guess you ran out of space

Step-by-step explanation:

I think you have to prove that you get a line. Just take the limit of the resulting remainder. That goes to zero.

Answer:

In a division algorithm, [tex]p(x)[/tex] refers to the dividend polynomial, [tex]d(x)[/tex] refers to the divisor polynomial, [tex]q(x)[/tex] refers to the quotient polynomial and [tex]r(x)[/tex] refers to the residula polynomial.

The division algorithm is defined as

[tex]p(x)=d(x) \times q(x) +r(x)[/tex]

Where [tex]p(x)\geq d(x)[/tex] and [tex]d(x) \neq 0[/tex], other wise the algorithm won't be defined.

So, the complete paragraph is: "if [tex]p(x)[/tex] and [tex]d(x)[/tex] are polynomial functions with [tex]d(x)\neq 0[/tex] and the degree of [tex]d(x)[/tex] is less than or equal to the degree of [tex]p(x)[/tex], then there exist unique polynomial functions [tex]q(x)[/tex] and [tex]r(x)[/tex] such that  [tex]p(x)=d(x) \times q(x) +r(x)[/tex].

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