nightmarecrash2 nightmarecrash2
  • 30-03-2019
  • Mathematics
contestada

Write an equation of the circle whose radius is 3 and whose center is (-1,6).

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wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 30-03-2019

Answer:

(x+1)^2 + (y-6)^2 = 3^2

Step-by-step explanation:

The general equation for a circle is given by

(x-h)^2 + (y-k)^2 = r^2

where (h,k) is the center and r is the radius

Substituting in the point (-1,6) and the radius 3

(x--1)^2 + (y-6)^2 = 3^2

(x+1)^2 + (y-6)^2 = 3^2

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