Respuesta :

Answer:

[tex]m<A.M.E=58\°[/tex]

Step-by-step explanation:

step 1

Find the measure of angle M.E.F

we know that

In an inscribed quadrilateral opposite angles are in fact supplements for each other

so

[tex]m<M.A.F+m<M.E.F=180\°[/tex]

[tex]m<M.E.F=180\°-75\°=105\°[/tex]

step 2

Find the measure of arc M.A.F

we know that

The inscribed angle measures half that of the arc comprising

so

[tex]m<M.E.F=\frac{1}{2}(arc\ M.A.F)[/tex]

we have

[tex]m<M.E.F=105\°[/tex]

substitute

[tex]105\°=\frac{1}{2}(arc\ M.A.F)[/tex]

[tex]arc\ M.A.F=210\°[/tex]

step 3

Find the measure of arc A.F

[tex]arc\ M.A.F=arc\ A.M+arc\ A.F[/tex]

we have

[tex]arc\ M.A.F=210\°[/tex]

[tex]arc\ A.M=125\°[/tex]

substitute

[tex]210\°=125\°+arc\ A.F[/tex]

[tex]arc\ A.F=210\°-125\°=85\°[/tex]

step 4

Find the measure of angle A.M.E

we know that

The inscribed angle measures half that of the arc comprising

so

[tex]m<A.M.E=\frac{1}{2}(arc\ A.F.E)[/tex]

we have

[tex]arc\ A.F.E=arc\ A.F+arc\ E.F=85\°+31\°=116\°[/tex]

substitute

[tex]m<A.M.E=\frac{1}{2}(116\°)=58\°[/tex]

The angle ∠AME is the angle subtended at the circumference by the arc [tex]m \widehat{EFA}[/tex].

Correct response:

  • m∠AME is 58°

Methods used for the calculation:

The given parameters are;

[tex]m \widehat{AM}[/tex] = 125°

[tex]m\widehat{EF}[/tex] = 31°

m∠MAF = 75°

Required:

m∠AME


Solution:

[tex]m \widehat{MEF}[/tex] = 2 × m∠MAF

Therefore;

[tex]m \widehat{MEF}[/tex] = 2 × 75° = 150°

[tex]m \widehat{AM}[/tex] + [tex]m \widehat{MEF}[/tex] + [tex]m \widehat{FA}[/tex] = 360° sum of arcs of a circle postulate

Therefore;

[tex]m \widehat{FA}[/tex] = 360° - ([tex]\mathbf{m \widehat{AM}}[/tex] + [tex]\mathbf{m\widehat{MEF}}[/tex])

Which gives;

[tex]m\widehat{FA}[/tex] = 360° - (125° + 150°) = 85°

  • [tex]m \widehat{EFA}[/tex] = [tex]\mathbf{m \widehat{FA}}[/tex] + [tex]\mathbf{m \widehat{EF}}[/tex]

Therefore;

[tex]m\widehat{EFA}[/tex] = 85° + 31° = 116°

[tex]m \widehat{EFA}[/tex] = 2 × m∠AME (angle at center is twice angle at the circumference)

Therefore;

[tex]m\angle AME = \mathbf{\dfrac{m \widehat{EFA}}{2} }[/tex]

[tex]m \angle AME = \dfrac{116^{\circ}}{2} = 58^{\circ}[/tex]

  • m∠AME = 58°

Learn more about circle theorems here:

https://brainly.com/question/16879446

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