Question

(7+u)^2−(5+u)^2=6v, (2−v)^2−(6−v)^2=4u.

Answer 1

Solve for u in (7 + u)^2 - (5 + u)^2 = 6v

u = 3(v - 4)/2

Substitute u = 3(v - 4)/2 into (2 - v)^2 - (6 - v)^2 = 4u

8v - 32 = 6(v - 4)

Solve for v in 8v - 32 = 6(v - 4)

v = 4

Substitute v = 4 into u = 3(v - 4)/2

u = 0

Therefore,

u = 0

v = 4