Answer: [tex]\bold{3\sqrt{2x}-36\sqrt x}[/tex]
Step-by-step explanation:
[tex]7(3\sqrt{2x})-3(3\sqrt{16x})-3(3\sqrt{8x})\\\\=21\sqrt{2x}-9\sqrt{16x}-9\sqrt{8x}\\\\=21\sqrt{2x}-9\cdot 4\sqrt x-9\cdot 2\sqrt{2x}\\\\=21\sqrt{2x}-36\sqrt x-18\sqrt{2x}\\\\=(21-18)\sqrt{2x}-36\sqrt x\\\\=3\sqrt{2x}-36\sqrt x[/tex]