How Would I Find The Answer ?

Answer: B. 34°
Step-by-step explanation:
∠RQS + ∠SQT = ∠RQT
[tex]\bigg(\dfrac{1}{2}x+4\bigg)+\bigg(\dfrac{3}{4}x-6\bigg)=2x-47\\\\\\.\qquad\qquad\qquad\dfrac{5}{4}x-2=2x-47\\\\\\.\qquad\qquad\qquad\quad -2=\dfrac{3}{4}x-47\\\\\\.\qquad\qquad\qquad\qquad 45=\dfrac{3}{4}x\\\\\\.\qquad\qquad\qquad\qquad 180=3x\\\\\\.\qquad\qquad\qquad\qquad 60=x[/tex]
[tex]\angle RQS=\dfrac{1}{2}x+4\\\\.\qquad=\dfrac{1}{2}(60)+4\\\\.\qquad=30+4\\\\.\qquad=34[/tex]