What is the measure of the inscribed angle ABC if the measure of the arc, which this angle intercepts is: 48, 57, 90, 124, 180.

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The rule is:

The inscribed angle would be half the measure of the intercepted arc

If the arc was 48, the inscribed angle = 48/2 = 24 degrees

If the arc was 57, the inscribed angle = 57/2 = 28.5 degrees

If the arc was 90, the inscribed angle = 90/2 = 45 degrees

If the arc was 124, the inscribed angle = 124/2 = 62 degrees

If the arc was 180, the inscribed angle = 180/2 = 90 degrees

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↬ ʜᴀɴɴᴀʜ

I hope you understand it well :)

The measure of an inscribed angle is half the measure intercepted arc.

With that rule

  • If the arc is 48 the inscribed angle would be [tex]\frac{48}{2}=24[/tex]
  • If the arc is 57 the inscribed angle would be [tex]\frac{57}{2}=28.5[/tex]
  • If the arc is 90 the inscribed angle would be [tex]\frac{90}{2}=45[/tex]
  • If the arc is 124 the inscribed angle would be [tex]\frac{124}{2}=62[/tex]
  • If the arc is 180 the inscribed angle would be [tex]\frac{180}{2}=90[/tex]

Hope this helps :)

If you have a doubt just reply over here, I would be happy to help you further :)

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