Question

solve on the interval [0,2pi]

3sec x -2 = 1

Answer 1

Answer:

Final answer is $x=0$ and $x=2\pi$.

Step-by-step explanation:

Given equation is $3\cdot\sec\left(x\right)-2=1$

Now we need to find the solution of  $3\cdot\sec\left(x\right)-2=1$ in given interval $[0, 2\pi ]$.

$3\cdot\sec\left(x\right)-2=1$

$3\cdot\sec\left(x\right)=1+2$

$3\cdot\sec\left(x\right)=3$

$\frac{3\cdot\sec\left(x\right)}{3}=\frac{3}{3}$

$\sec\left(x\right)=1$

which gives $x=0$ and $x=2\pi$ in the given interval.

Hence final answer is $x=0$ and $x=2\pi$.

Answer 2

Answer:

x  = 0 and x = 2π

Step-by-step explanation:

We have given the equation.

3sec x -2 = 1

We have to solve it  interval [0,2pi].

3sec x -2 = 1

3secx = 1+2

3secx = 3

secx = 1

x= sec⁻¹(1)

x  = 0 and x = 2π is the answer in this interval.