Answer:
line d
Step-by-step explanation:
Convert the equation to the slope-intercept form (y = mx + b):
[tex]2x+5y=-10[/tex] subtract 2x from both sides
[tex]5y=-2x-10[/tex] divide both sides by 5
[tex]y=\-\dfrac{2}{5}x-2[/tex]
Put x = 0 to the equation of a line:
[tex]y=-\dfrac{2}{5}(0)-2=-0-2=-2\to(0,\ -2)[/tex]
The lines c and d passes through that's point.
Put x = 5 to the equation of a line:
[tex]y=-\dfrac{2}{5}(5)-2=-2-2=-4\to(5,\ -4)[/tex]
The line d passes through that point.
