= 13.629 g of ZnCl2
The equation for the reaction.
Zn(s)+2HCL(aq)=>ZnCl2(aq)+H2(g)
Number of moles of Zinc;
Moles = mass/RAM
= 6.5 g/65g/mol
= 0.1 moles
The mole ration of Zn : ZnCl2 is 1 : 1
Therefore, number of moles of ZnCl2 is 0.1 moles
Mass = moles × Molar mass
= 0.1 ×136.286 g/mol
= 13.629 g