Question

What are the center and radius of a circle with standard form equation (x+3) square + (y+8) square =6

Answer 1

Answer:

centre = (- 3, - 8), radius = $\sqrt{6}$

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x + 3)² + (y + 8)² = 6 ← is in standard form

with centre = (- 3, - 8) and r = $\sqrt{6}$