Solve by taking the square root of both sides

Answer:
option B
x = 1 + 3√6 or x = 1 - 3√6
Step-by-step explanation:
Given in the question an equation,
3(x-1)² - 162 = 0
rearrange the x terms to the left and constant to the right
3(x-1)² = 162
(x-1)² = 162/3
(x-1)² = 54
Take square root on both sides
√(x-1)² = √54
x - 1 = ±3√6
x = ±3√6 + 1
So we have two values for x
x = 3√6 + 1 OR x = -3√6 + 1
Answer:
b.x = 1+3√6, 1-3√6
Step-by-step explanation:
We have given a quadratic equation.
3(x-1)²-162 = 0
We have to find the solution of given equation by taking the square root of both sides.
Simplifying above equation, we have
3(x-1)² = 162
Dividing above equation by 3, we have
(x-1)² = 54
Taking square root to both sides of equation, we have
x-1 = ±√54
x = ±√54+1
x = ±√(9×6)+1
x = ±3√6+1
x = 1+3√6, 1-3√6 which is the solution of given equation.