Question

In ΔVWX, the measure of ∠X=90°, XV = 27 feet, and WX = 57 feet. Find the measure of ∠V to the nearest degree.

Answer 1

Answer:

$<V=65\°$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

In the right triangle VWX

$tan(V)=\frac{WX}{XV}$ -----> opposite side angle V divided by the adjacent side angle V

substitute the values

$tan(V)=\frac{57}{27}$

$<V=arctan(\frac{57}{27})=65\°$