Question

Hexagon IJKLMN is shown on the coordinate plane below:

Hexagon IJKLMN on a coordinate plane with ordered pairs at I negative two, six, at J four, four, at K six, negative one at, L n

If hexagon IJKLMN is dilated by a scale factor of two fifths from the origin to create hexagon I'J'K'L'M'N', what is the ordered pair of point I'? (4 points)



A) (−0.8, 2.4)

B) (−5, 15)

C) (−2.5, 5)

D) (−0.4, 0.8)

Answer 1

Answer:

Option: A is the correct answer.

The ordered pair of point I' are:

         A)   (-0.8,2.4)

Step-by-step explanation:

We know than if any point A with vertices as (a,b) are dilated by a scale factor of k then the vertices of the transformed point is:

       A(a,b) → A'(ka,kb)

We are given vertices of point I as:

                   I(-2,6)

Hence, the vertices of the transformed point I' after dilating by a scale factor of 2/5 is:

         I(-2,6) → I'(-2×(2/5),6×(2/5))

⇒  I(-2,6) → I'(-0.8,2.4)

      Hence, option: A is the answer.

                 A)  (-0.8,2.4)                              

Answer 2

Answer: (-0.8,2.4)

Step-by-step explanation:

We know than if any point (a,b) are dilated by a scale factor of k from the origin then the vertices of the image point is :

$A(a,b) \rightarrow A'(ka,kb)$

Given : Hexagon IJKLMN on a coordinate plane with ordered pairs at I (-2,6).

Then, the coordinates of the image point I' after dilating by a scale factor of $\dfrac{2}{5}$ will be :

$I (-2,6) \rightarrow I'(-2\times\dfrac{2}{5},6\times\dfrac{2}{5})\\\\=(-0.8, 2.4)$

Hence, the ordered pair of point I' =(-0.8, 2.4)