What is the exact value? (Picture provided)

Answer:
b. (√15)/4
Step-by-step explanation:
Since Sin Ф = (opposite side)/Hypotenuse, we have 2 sides of a right triangle.
Use Pythagorean theorem to solve for the missing leg (the adjacent side)
1² + b² = 4²
1 + b² = 16
b² = 15
b = √15
So the adjacent side is √15, so Cos Ф = (√15)/4
Answer:
b. [tex]\frac{\sqrt{15}}{4}[/tex]
Step-by-step explanation:
Given that [tex]\sin(\theta)=\frac{1}{4}[/tex] where [tex]0\:<\: \theta \:<\:\frac{\pi}{2}[/tex].
Recall and use the Pythagorean Identity;
[tex]\sin^2(\theta)+\cos^2(\theta)=1[/tex]
This implies that;
[tex](\frac{1}{4})^2+\cos^2(\theta)=1[/tex]
[tex]\frac{1}{16}+\cos^2(\theta)=1[/tex]
[tex]\cos^2(\theta)=1-\frac{1}{16}[/tex]
[tex]\cos^2(\theta)=\frac{15}{16}[/tex]
Take the square root of both sides;
[tex]\cos(\theta)=\pm \sqrt{\frac{15}{16}}[/tex]
[tex]\cos(\theta)=\pm \frac{\sqrt{15}}{4}[/tex]
Since we are in the first quadrant;
[tex]\cos(\theta)=\frac{\sqrt{15}}{4}[/tex]