Question

A rectangle has vertices at (-1, 6), (-1, -2), (3, 6), and (3,-2). What is the area of the rectangle?

Answer 1

Answer:

32 units²

Step-by-step explanation:

From point 1 to point 2, the y values change by 8 units while the x values stay the same.  This side of the rectangle has a length of 8

From point 1 to point 3, the x values change by 4 units while the y values stay the same.  This side of the polygon has a length of 4

The area of the rectangle is 8x4 = 32 units²

Answer 2

Answer:

32 square units

Step-by-step explanation:

A rectangle has vertices at (-1, 6), (-1, -2), (3, 6), and (3,-2)

Area of a rectangle = length times width

LEts find the distance between  (-1, 6) and  (3, 6)

Apply distance formula

$D= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$D= \sqrt{(3+1)^2+(6-6)^2}=\sqrt(16)= 4$

LEts find the distance between   (-1, 6), (-1, -2)

$D= \sqrt{(-1+1)^2+(-2-6)^2}=\sqrt(64)= 8$

Area of the rectangle = 4 times 8= 32 square units