Answer:
[tex]\large\boxed{3x-4y=30}[/tex]
Step-by-step explanation:
[tex]\dfrac{1}{2}x-\dfrac{2}{3}y=5\qquad\text{multiply both sides by LCM(2, 3) = 6}\\\\6\!\!\!\!\diagup^3\cdot\dfrac{1}{2\!\!\!\!\diagup_1}x-6\!\!\!\!\diagup^2\cdot\dfrac{2}{3\!\!\!\!\diagup_1}y=6\cdot5\\\\(3)(x)-(2)(2y)=30\\\\3x-4y=30[/tex]