Question

f(t)=3-2t.2t+t write in standard form

Answer 1

Hello!

The answer is: $f(t)=-4t^{2}+t+3$

Why?

Since we are given a quadratic function, we need to write it using the standard form of quadratic function (parabola).

The given function is:

$f(t)=3-2t.2t=+t$

The standard form of a parabola is:

$f(t)=a^{2}+bx+c$

Where,

a is equal to the quadratic variable coefficient

b is equal to the linear variable coefficient

c is the constant number

So, writing the function in the standard form will be:

$f(t)=3-2t*2t+t=3-4t^{2}+t=-4t^{2}+t+3$

$f(t)=-4t^{2}+t+3$

Where,

$a=-4\\b=1\\c=3$

Have a nice day!