Answer:
Option D 6 is the answer.
Step-by-step explanation:
the given points are A, D, C and B. If each point in the diagram can act as end points, we have to calculate number of distinct line segments formed.
This ca be calculated in two ways.
(1) We will form the line segments
AB, AC, AD, BC, BD, DC
Therefore 6 segments can be formed.
(2) By combination method
Number of segments = [tex]^{4}C_{2}[/tex]
= [tex]\frac{4!}{2!2!}=\frac{4\times 3\times 2\times 1}{(2\times 1)\times (2\times 1)}[/tex]
= [tex]\frac{4\times 3}{2\times 3}=\frac{12}{2}[/tex]
= 6
Option D 6 is the answer.
