Answer:
Part a) The drawn in the attached figure
Part b)The slant height of the outside edge is [tex]x=10\ in[/tex]
Step-by-step explanation:
Part a) The drawn in the attached figure
Part b) What is the slant height of the outside edge?
we have that
The diameter of the base of the cone is 12 in
so
[tex]r=12/2=6\ in[/tex] ----> the radius is half the diameter
[tex]h=8\ in[/tex]
Applying the Pythagoras Theorem find the slant height x
[tex]x^{2}=r^{2}+h^{2}[/tex]
substitute the values
[tex]x^{2}=6^{2}+8^{2}\\x^{2}=100\\x=10\ in[/tex]