Answer: [tex]\bold{\dfrac{-2\pm \sqrt{22}}{3}}[/tex]
Step-by-step explanation:
[tex]3x^2+4x-6=0\quad \rightarrow \quad a=3,\ b=4,\ c=-6\\\\\\\text{Quadratic formula is: }x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(4)\pm \sqrt{(4)^2-4(3)(-6)}}{2(3)}\\\\\\.\ =\dfrac{-4\pm \sqrt{16+72}}{2(3)}\\\\\\\\.\ =\dfrac{-4\pm \sqrt{88}}{2(3)}\\\\\\\\.\ =\dfrac{-4\pm 2\sqrt{22}}{2(3)}\\\\\\\\.\ =\dfrac{-2\pm \sqrt{22}}{3}[/tex]
