What is the area of this triangle?

We use the vertical side as the base: it is a vertical segment, so it's length is the difference of the y coordinates of its endpoints:
[tex] b = y_2-y_1[/tex]
The height would be the segment starting from [tex](x_3,y_3)[/tex], perpendicular to the base. Since this is a horizontal segment, its length is the difference of the x coordinates of its endpoints:
[tex]h = x_3-x_1[/tex]
So, the area is given by
[tex]A = \dfrac{bh}{2} = \dfrac{(y_2-y_1)(x_3-x_1)}{2}[/tex]
Answer:
A = 18
Step-by-step explanation:
Drop a perpendicular from (x₃, y₃) to point A on the opposite side.
The vertical line containing A is the base of the triangle, and the horizontal line is its height,
The formula for the area of a triangle is
A = ½bh
b = y₂ - y₁ = 6
h = x₃ - x₁ = 6
A = ½ × 6 × 6 = 18
The area of the triangle is 18.