Respuesta :
Answer:
Yes, the right angle is angle C.
Step-by-step explanation:
The given triangle has vertices at A(–2, 3), B(–3, –6), and C(2, –1).
Recall the slope formula;
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
The slope of the line going through AC is
[tex]m_{AC}=\frac{-1-3}{2--2}=-1[/tex]
The slope of the line going through BC s
[tex]m_{AC}=\frac{-1--6}{2--3}=1[/tex]
The product of the slopes of AC and BC is [tex]-1\times1=-1[/tex]
This means line AC is perpendicular to BC at C.
Hence the triangle ABC is right angled at C.