Here is your answer
[tex]<b>5 watts</b>[/tex]
REASON :
Given,
t= 20 secs
F= 20 N
s (displacement)= 5m
Now,
Power= \frac{Work done}{time}
P= W/t ...... (i)
W= F×s×cos(theta)
W= 20×5 × 1 (theta is 0 degree; so cos0= 1)
W= 100 J
Hence,
P= 100/20 (from eq. i)
P= 5 watts
HOPE IT IS USEFUL