Answer:
[tex]y=2\cdot4^x\\y=4\cdot\left(\frac{1}{2}\right)^x[/tex]
Step-by-step explanation:
We're given both the y-intercept and a point on the graphs of both functions, so our work her is largely just substituting x and y values in the general form of the equation for an exponential function.
For the first one, we can start by using the point (0, 2) to solve for a:
[tex]y=a\cdot b^x\\2=a\cdot b^0\\2=a[/tex]
Next, we can use that a-value and the second point to solve for b:
[tex]y=2\cdot b^x\\128=2\cdot b^3\\64=b^3\\4=b[/tex]
This gives us the equation [tex]y=2\cdot4^x[/tex] for the first function.
We can repeat the same process for the second function. Solving for a:
[tex]y=a\cdot b^x\\4=a\cdot b^0\\4=a[/tex]
And then for b, using the point (2, 1):
[tex]1=4\cdot b^2\\\frac{1}{4}=b^2\\\frac{1}{2}=b[/tex]
This gives us the general equation [tex]y=4\cdot\left(\frac{1}{2}\right)^x[/tex]