it is neither, it cannot be raised to a power unless it is 0 or 1 :)
The function is neither an odd function nor an even function
The function is given as:
f(x)=2x^3-x^2
Calculate f(-x)
f(-x)= 2(-x)^3 - (-x)^2
f(-x)= -2x^3 - x^2
Calculate -f(x)
-f(x)= -2x^3 + x^2
From the above computation,
f(x), f(-x) and -f(x) are not equal
Hence, the function is neither an odd function nor an even function
Read more about functions at:
https://brainly.com/question/17059941