Question

Find the inverse function:
Given F(x)= (8-2x)^2

Answer 1

Answer:

$y=\frac{\sqrt{x} -8}{-2}$

Step-by-step explanation:

To find an inverse, switch x and y values in the equation. Then solve for y.

$F(x) = (8-2x)^2\\x = (8-2y)^2\\\sqrt{x} = 8 - 2y\\\sqrt{x} -8 = -2y\\\frac{\sqrt{x} -8}{-2} =y$