Respuesta :

[tex]\bf \textit{Pythagorean Identities} \\\\ sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{cos^2(\theta )-cos^4(\theta )}{tan(\theta )}\implies \cfrac{cos^2(\theta )[1-cos^2(\theta )]}{\frac{sin(\theta )}{cos(\theta )}}\implies \cfrac{cos^2(\theta )[sin^2(\theta )]}{\frac{sin(\theta )}{cos(\theta )}} \\\\\\ \cfrac{cos^2(\theta )[sin^2(\theta )]}{1} \cdot \cfrac{cos(\theta )}{sin(\theta )}\implies cos^3(\theta )sin(\theta )[/tex]

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