Answer:
The length of its diagonal is [tex]27.01\ m[/tex]
Step-by-step explanation:
Let
b------> the length side of the square
d-----> the diagonal of the square
we know that
The perimeter of the square is
[tex]P=4b[/tex]
[tex]P=76.4\ m[/tex]
Find the value of b
[tex]4b=76.4[/tex]
[tex]b=76.4/4=19.1\ m[/tex]
Applying the Pythagoras theorem find the length of the diagonal
[tex]d^{2}=19.1^{2}+19.1^{2}\\ \\d^{2}=729.62\\ \\ d=27.01\ m[/tex]
