Respuesta :

Answer:

4

Step-by-step explanation:

Given in the question a logarithm expression

[tex]7^(log_{49}16 )[/tex]

We will use Exponent of Log Rule

[tex]b^(log_{b}k ) = k[/tex]

here b = 7

        k = 16

So suppose

[tex]7^(log_{49}16 ) = x\\Take square on both sides\\(7^(log_{49}16 ) )^{2} = x^2\\49^(log_{49}16)= x^2[/tex]

Now, according to the rule

16 = x²

to find x only take square root on both sides of the equation

x = √16

x = 4

so [tex]7^(log_{49}16 )[/tex] = 4

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