Question

Match the rational expression

Answer 1

Answer:

Step-by-step explanation:

$1) (x-2)+\frac{6}{x-2} \\=\frac{(x-2)(x-2)+6}{x-2}\\ =\frac{x^{2}-4x+4+6}{x-  2}\\=\frac{x^{2}-4x+10}{x-2}$

$2)(x+3)+\frac{10}{x-2} \\=\frac{(x+3)(x-2)+10}{x-2}\\ =\frac{x^{2}+3x-2x-6+10}{x-2}\\=\frac{x^{2}+x+4}{x-2}$

$3)(x+1)+\frac{6}{x-2} \\=\frac{(x+1)(x-2)+6}{x-2}\\ =\frac{x^{2}-2x+x-2+6 }{x-2}\\=\frac{x^{2}-x+4}{x-2}$

$4)(x-3)+\frac{10}{x-2} \\=\frac{(x-3)(x-2)+10}{x-2}\\ =\frac{x^{2}-3x-2x+6+10 }{x-2}\\=\frac{x^{2}-5x+14}{x-2}$