Answer:
162.0 g.
Explanation:
- The solubility is the maximum amount of solute dissolved in a given amount of solvent to form saturated solution.
The solubility of NaNO₃ in 100.0 g of water at 10.0°C is 81.0 g/ 100 g water.
Using cross multiplication:
81.0 g of NaNO₃ form saturated solution at 10.0°C in → 100.0 g of water.
???? g of NaNO₃ form saturated solution at 10.0°C in → 200.0 g of water.
∴ The grams of NaNO₃ form saturated solution at 10.0°C in 200.0 g of water = (81.0 g)(200.0 g)/(100.0 g) = 162.0 g.
