Respuesta :
Here is your answer
a) x=-2, -3
REASON :
[tex] f(x)= {x}^{2}+5x+6[/tex]
= [tex] {x}^{2}+2x+3x+6 [/tex]
= [tex] x(x+2)+3(x+2) [/tex]
= [tex] (x+2)(x+3) [/tex]
To find zeroes
f(x)= 0
So,
(x+2)(x+3)=0
[tex] x=-2 or x=-3 [/tex]
HOPE IT IS USEFUL
a) x=-2, -3
REASON :
[tex] f(x)= {x}^{2}+5x+6[/tex]
= [tex] {x}^{2}+2x+3x+6 [/tex]
= [tex] x(x+2)+3(x+2) [/tex]
= [tex] (x+2)(x+3) [/tex]
To find zeroes
f(x)= 0
So,
(x+2)(x+3)=0
[tex] x=-2 or x=-3 [/tex]
HOPE IT IS USEFUL
