Question

multiply and simplify (x+3) squared

Answer 1

x^2 + 6x + 9



(x + 3)^2

(x + 3)(x + 3)

Use the FOIL method.

First term in each binomial: x * x = x^2
Outside terms: x * 3 = 3x
Inside terms: 3 * x = 3x
Last term in each binomial: 3 * 3 = 9

Now just add.

x^2 + 3x + 3x + 9

x^2 + 6x + 9



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Answer 2

Answer:

$\large\boxed{(x+3)^2=x^2+6x+9}$

Step-by-step explanation:

Use the FOIL: (a + b)(c + d) = ac + ad + bc + bd

$(x+3)^2=(x+3)(x+3)\\\\=(x)(x)+(x)(3)+(3)(x)+(3)(3)\\\\=x^2+3x+3x+9\qquad\text{combine like terms}\\\\=x^2+(3x+3x)+9\\\\=x^2+6x+9$

You can use

$(a+b)^2=a^2+2ab+b^2$

$(x+3)^2=x^2+2(x)(3)+3^2=x^2+6x+9$