Question

Write formation reactions for the following. [You must include the states of matter for each atom or compound.] a. Ca(NO3)2 (s), b. CH3OH (l), c. NaClO4 (s)

Answer 1

Answer:

a. Ca(s) + N₂(g) + 3O₂(g) → Ca(NO₃)₂(s).

b. C(s,graphite) + 2H₂(g) + 1/2O₂(g) → CH₃OH(l).

c. 3NaCl(s) + 4O₃(g) → 3NaClO₄(s).

Explanation:

a. The formation reaction of Ca(NO₃)₂(s) is:

Ca(s) + N₂(g) + 3O₂(g) → Ca(NO₃)₂(s).

• 1.0 mole of solid Ca reacts with 1.0 mole of N₂ gas and 3.0 moles of O₂ gas to produce 1.0 mole of solid Ca(NO₃)₂.

b. The formation reaction of CH₃OH(l) is:

C(s,graphite) + 2H₂(g) + 1/2O₂(g) → CH₃OH(l).

• 1.0 mole of solid C (graphite) reacts with 2.0 mole of H₂ gas and 0.5 mole of O₂ gas to produce 1.0 mole of liquid CH₃OH.

c. The formation reaction of NaClO₄(s) is:

3NaCl(s) + 4O₃(g) → 3NaClO₄(s).

• 3.0 moles of solid NaCl react with 4.0 moles of O₂ gas to produce 3.0 moles of solid NaClO₄.

Answer 2

The formation reactions include:

a. Ca(s) + N₂(g) + 3O₂(g) → Ca(NO₃)₂(s).

1 mole of solid Calcium reacts with 1 mole of Nitrogen gas and 3 moles of Oxygen gas to produce 1 mole of solid Calcium nitrate.

b. C(s) + 2H₂(g) + 1/2O₂(g) → CH₃OH(l).

1 mole of solid Carbon reacts with 2 mole of Hydrogen gas and 1/2 mole of Oxygen gas to produce 1 mole of liquid methanol

c. 3NaCl(s) + 4O₃(g) → 3NaClO₄(s).

3 moles of solid Sodium chloride react with 4 moles of Oxygen gas to produce 3 moles of solid sodium perchlorate.

Read more on https://brainly.com/question/12373196