Two shirts are removed from a dryer and attract each other with a force of 0.5N while they are separated by 1 cm. If the two shirts are equally charged, what would their charge and the force be if they are separated by 4 cm?

Respuesta :

1) Charge: [tex]7.5\cdot 10^{-8} C[/tex]

Explanation:

The electrostatic force between the two shirts is:

[tex]F=k\frac{q_1 q_2}{r^2}[/tex]

where

k is the Coulomb's constant

q1 = q2 = q is the charge of each shirt (they are equally charged)

r = 4 cm = 0.04 m is the distance between the shirts

F = 0.5 N is the force

Re-arranging the equation, we can find q, the charge of each shirt:

[tex]q=\sqrt{\frac{Fr^2}{k}}=\sqrt{\frac{(0.5 N)(0.01 m)^2}{9\cdot 10^9}}=7.5\cdot 10^{-8} C[/tex]

2) Force if they are separated by 4 cm: 0.03 N

In this case, the force between the two shirts would be:

[tex]F=k\frac{q_1 q_2}{r^2}=(9\cdot 10^9)\frac{(7.5\cdot 10^{-8}C)^2}{(0.04 m)^2}=0.03 N[/tex]

Answer:

C. 7.4E-6C, 0.03 N

Explanation:

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