When aluminum, Al, metal is dipped in an aqueous solution of hydrochloric acid, HCl, hydrogen gas, H2, is produced with the formation of an aluminum chloride, AlCl3, solution. Write the balanced chemical equation showing the phases of reactants and products.

We should apply the law of conversation of mass to balance any chemical reaction; that the no. of atoms in the reactants side is equal to that in the products side.

So, the balanced equation is:

Al(s) + 3HCl(aq) → AlCl₃(aq) + 3/2H₂(g).

Answer Link

nimamprayogo nimamprayogo · Answer 2 · 2020-01-12T20:26:52+01:00

Further explanation

Aluminum chloride (AlCl3) is the main chemical compound of aluminum and chlorine. This compound is white, but the sample is often contaminated with iron trichloride, which gives a yellow coloring. the density has a low melting and boiling point. This compound is mainly produced and consumed in the production of aluminum metal, but a large amount is also used in the chemical industry. This compound is often classified as Lewis acid. This is an example of an inorganic compound that cracks at low temperatures, changing back and forth from a polymer to a monomer.

Al = Aluminum metal

HCl = hydrochloric acid solution

AlCl₃ = aluminum chloride

H₂ = Hydrogen gas

Al (s) + HCl (aq) ⇒ AlCl₃ (aq) + H₂ (g)

To equalize the reaction coefficient with the following steps:

Step 1 Determine the reaction coefficient for the compound AlCl₃ = 1, so the reaction becomes: Al (s) + HCl (aq) ⇒ AlCl₃ (aq) + H₂ (g)

Step 2, because the Cl atom after the reaction = 2 then before the reaction in HCl must be = 3 so the coefficient of HCl = 3, the reaction becomes: Al (s) +3 HCl (aq) ⇒ AlCl₃ (aq) + H₂ (g)

Step 3. Because the number of H atoms in HCl = 3, the number of H atoms in H₂ must be multiplied by 3/2, so that it becomes

Al (s) + 3HCl (aq) ⇒ AlCl₃ (aq) +3/2 H₂ (g)

Step 4, so that there are no fractional numbers, we multiply all reactions by 2, so that it becomes (Al (s) + 3HCl (aq) ⇒ AlCl₃ (aq) + 3 / 2H₂ (g)) x 2

thus becoming ;

2Al (s) + 6HCl (aq) ⇒ 2AlCl₃ (aq) + 3H₂ (g)

if we count, the number of atoms before the reaction is the same as after the reaction:

2Al (s) + 6HCl (aq) ⇒ 2AlCl₃ (aq) + 3H₂ (g)

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Aluminum chloride : https://brainly.com/question/12337635

Details

Class: high school

Subject: chemistry

Keywords : Aluminum chloride