Answer:
The total area of the figure is [tex]22.5\ in^{2}[/tex]
Step-by-step explanation:
we know that
The area of the figure is equal to the area of the rectangle plus the area of the isosceles right triangle
Find the area of rectangle
[tex]A=(6)(3)=18\ in^{2}[/tex]
Find the area of the isosceles right triangle
[tex]A=\frac{1}{2}(3)(3)=4.5\ in^{2}[/tex]
Find the total area of the figure
[tex]18\ in^{2}+4.5\ in^{2}=22.5\ in^{2}[/tex]