Question

a spherical marble has a radius of 0.6 cm what is the approximate volume of the marble?
a. 0.68cm^3
b. 0.90 cm^3
c.1.51 cm^3
d. 7.24cm^3

Answer 1

Answer: option b

Step-by-step explanation:

You must apply the formula for calculate the volume of a sphere, which is shown below:

$V=\frac{4}{3}r^{3}\pi$

Where r is the radius ($r=0.6cm$)

When you substitute values into the formula you obtain that the volume of the marble is the following:

$V=\frac{4}{3}(0.6cm)^{3}\pi=0.90cm^{3}$

Answer 2

Answer:

b. 0.90 cm^3

Step-by-step explanation:

Here we have to use the formula.

Volume of a spherical V = 4/3 πr^3

Given: r = 0.6 cm

Now plug in r = 0.6 in the above formula, we get

V = 4/3 π*(0.6)^3

V = 4/3*3.14*0.216       [π = 3.14]

V = 2.71296/3

V= 0.90432

When we round to the nearest hundredths place, we get

V = 0.90 cm^3

Hope this will helpful.

Thank you.