Question

Which of the following correctly shows the area of one of the figures in the net? Please see attachment and Figure C 168 square units is incorrect. Thanks!

Answer 1

Answer: Option d.

Step-by-step explanation:

You must apply the formulas for calculate:

- The area of a rectangle:

 $Area[rectangle}=lenght*width$

- The area of a triangle:

$A{triangle}=\frac{base*height}{2}$

Then, you have that the areas are:

1. The area of figure A is:

$A=28*7=196units^{2}$

2.  The area of figure B is:

$A=\frac{bh}{2}=\frac{7*24}{2}=84units^{2}$

3. The area of figure C is:

 $A=24*28=672units^{2}$

4.  The area of figure E is:

$A=28*25=700units^{2}$

Therefore, as you can see the answer is the last option (option d).

Answer 2

Answer:

Figure E = 700 square units

Step-by-step explanation:

Surface area is nothing area of all the sides.

We can find the area of each figure add them together.

There are two triangles with the same measures.

Rectangle 1 with measure of 28 by 7.

Rectangle 2 with measure of 28  by 24

Rectangle 3 with measure of 28 by 25

Surface area = Area of two triangles + rectangle 1 + rectangle 2 + rectangle 3

Area of the triangle = 1/2 base* height

Area of the rectangle = length * width

Applying the formula, we get

Figure B = [1/2 (24*7)]  

Figure B = 84 square units

Figure A =  28*7

Figure A = 196 square units

Figure C  = Area of the rectangle 2 = 28*24 = 672 square units

Figure E  = Area of the rectangle 3 = 28*25 = 700 square units

The answer is

Figure E = 700 square units

Hope this will helpful.

Thank you.