Respuesta :
Answer:
The mean for the sampling distribution of the sample proportion is 0.29
The standard deviation for the sampling distribution of the sample proportion is 0.01435
Step-by-step explanation:
The mean for the sampling distribution of the sample proportion is always equal to the true population proportion, in this case; p = 0.29
The standard deviation for the sampling distribution of the sample proportion is calculated as;
[tex]\sqrt{\frac{p(1-p)}{n} }[/tex]
Using the given values;
p = 0.29
1 - p = 0.71
n = 1000
The standard deviation becomes;
[tex]\sqrt{\frac{(0.29)(1-0.29)}{1000} } \\[/tex]
The s.d becomes 0.01435
The mean and standard deviation for the sampling distribution of the sample proportion of American teenagers with a cell phone are:
- Mean = 0.29
- SD = 0.014
Recall:
- Sample distribution mean of a sample proportion = true population proportion.
- Formula for standard deviation of a sample distribution of a sample proportion is given as: [tex]\mathbf{\sqrt{\frac{p(1-p)}{n} } }[/tex]
Given that:
Population proportion, p, is 0.29
Therefore,
- Mean for the sample distribution of the sample proportion = 0.29.
Standard Deviation for the sampling distribution of the sample proportion of American teenagers with a cell phone = [tex]\mathbf{\sqrt{\frac{p(1-p)}{n} } }[/tex]
- Where,
p = 0.29
n = 1,000
- Substitute
[tex]SD = \sqrt{\frac{0.29(1-0.29)}{100} }\\\\SD = \sqrt{\frac{0.29(0.71)}{100}}\\\\SD = \sqrt{\frac{0.2059}{100}}\\\\\mathbf{SD = 0.014}[/tex]
Therefore, the mean and standard deviation for the sampling distribution of the sample proportion of American teenagers with a cell phone are:
- Mean = 0.29
- SD = 0.014
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