Question

Find the lateral area of the pyramid to the nearest whole number.

Answer 1

Answer:

$51m^2$

Step-by-step explanation:

The lateral area of the square pyramid is given by;

$A_L=a\sqrt{a^2+4h^2}$

where $a=4m,h=6m$.

We substitute the values to obtain;

$A_L=4\sqrt{4^2+4(6^2)}$

$A_L=4\sqrt{160}$

$A_L=16\sqrt{10}$

$A_L=50.5964$

$A_L\approx 51m^2$

Answer 2

Answer:

51m

Step-by-step explanation: