Question

Where does the line y=x-1 cross the y-axis?

Answer 1

Answer:

It would cross at (0, -1)

y = mx + c

The 'c' is the y intercept

Step-by-step explanation:

Answer 2

A line crossing y-axis has x coordinate zero at that point of crossing. The considered line $y=x-1$ crosses y-axis at point $(0, -1)$

How to find where does a function crosses x or y-axis?

Suppose that the line considered be of the form $y = f(x)$
The equation for y-axis is x = 0

Thus, intersection between both the curves is obtained by putting x = 0 in the considered function.

We get $x=0$ , and $y=f(0)$, Thus, the coordinate point of intersection with y-axis is $(0, f(0))$

And the equation for x-axis is $y = 0$

Thus, its intersection with given function is at y= 0 and y such that $f(x) = 0$

For the given case, we have the considered line as $y = x- 1$

To get its intersection with y-axis(which is x = 0), we put x = 0 in the given equation of line.

Thus,  $y = x - 1 = 0-1 = -1$

Thus, the point on the y-axis where the line $y = x-1$ intersects it is $(0, -1)$

Learn more about functions crossing axes here:

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