Question

what are the first three terms of the sequence...plz help pt.1​

Answer 1

$a_{n} \: = \: 2(a_{n - 1})^{2} \\ a_{1} = 4 \: (given) \\ a_{2} = \: 2(a_{2 - 1})^{2} \\ = 2(a_{ 1})^{2} \\ = 2 \times {4}^{2} \\ = 32 \\ \\ a_{3} = \: 2(a_{3 - 1})^{2} \\ = 2(a_{ 2})^{2} \\ = 2 \times {32}^{2} \\ = 2 \times 1024 \\ = 2048$

so first 3 terms are

4, 32, 2048

Answer 2

Answer:

The correct answer is option 3

4, 32, 2048

Step-by-step explanation:

It is given that,

a₁ = 4

aₙ = 2(aₙ₋₁)²

To find the second term

we have, aₙ = 2(aₙ₋₁)²

a₁ = 4

a₂ = 2(a₁)² = 2(4)² = 2 * 16 = 32

To find the third term

aₙ = 2(aₙ₋₁)²

a₂ = 32

a₃ = 2(a₂)² = 2(32)² = 2 * 1024 = 2048

Therefore the first three terms of the sequence are,

4, 32, 2048

The correct answer is option 3