You randomly draw a marble out of a bag that contains 202020 total marbles. 121212 of the marbles in the bag are blue. What is \text{P(draw a blue marble})P(draw a blue marble)P, left parenthesis, d, r, a, w, space, a, space, b, l, u, e, space, m, a, r, b, l, e, right parenthesis?

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It would be 121212/202020

This can be simplified to 3/5

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Answer: [tex]\text{P(draw an blue marble})=\dfrac{12}{20}=\dfrac{3}{5}[/tex]

Step-by-step explanation:

Given: The total number of marbles in a bag = 20

The number of blue marbles in the bag = 12

Then, the probability of drawing a blue marble is given by :-

[tex]\text{P(draw a blue marble)}=\dfrac{\text{Number of blue marbles}}{\text{Total marbles}}\\\\\Rightarrow\text{P(draw an blue marble})=\dfrac{12}{20}=\dfrac{3}{5}[/tex]