Answer:
9x^2 - 121
Step-by-step explanation:
Sum and difference: (a - b)(a + b) = a^2 - b^2
In this case:
(3x^2-11)(3x^2+11)
= (3x)^2 - 11^2
= 9x^2 - 121
[ Answer ]
[tex]\boxed{9x^{4} \ - \ 121}[/tex]
[ Explanation ]
Multiply The Following Polynomials
([tex]3x^{2}[/tex] - 11) * ([tex]3x^{2}[/tex] + 11)
=========================
Apply Difference Of Two Squares Formula
[tex](3x^{2})^{2} \ - \ 11^{2}[/tex]
Simplify
[tex](3x^{2})^{2 \ - \ 11^{2}[/tex]: [tex]9x^{4} \ - \ 121[/tex]
= [tex]9x^{4} \ - \ 121[/tex]
[tex]\boxed{[ \ Eclipsed \ ]}[/tex]
