Respuesta :
QUESTION 1a
The given function is:
[tex]5 {x}^{4} - 8[/tex]
By number of terms we classify this as a binomial.
By degree, we classify this as a quartic polynomial.
QUESTION 1b)
The given function is:
[tex]4 {a}^{2} - 2a - 16[/tex]
based on number of terms: trinomial
based on degree: quadratic polynomial.
QUESTION 1c
The given function is;
[tex]9 {m}^{3} [/tex]
Using number of terms: monomial
Using degree: cubic polynomial
QUESTION 2a.
Michael's weight:
[tex]72 {x}^{5} [/tex]
Al's weight:
[tex]9 {x}^{7} [/tex]
Ratio:
[tex]72 {x}^{5}:9 {x}^{7} [/tex]
QUESTION 1d
We need to simplify the ratio:
[tex]72 {x}^{5}:9 {x}^{7}[/tex]
We divide both terms in the ratio by;
[tex]9 {x}^{5} [/tex]
This gives us:
[tex]8:{x}^{2}[/tex]
QUESTION 1e
If the ratios were negative, then the ratio becomes:
[tex]72 {x}^{ - 5}:9 {x}^{ - 7} [/tex]
We divide each term of the ratio by,
[tex]9 {x}^{ - 7} [/tex]
This gives us;
[tex]8{x}^{ 2}:1[/tex]
Yes,that will change the answer.
QUESTION 2a
The given trinomials are;
[tex]{x}^{ 2}+7x-8[/tex]
and
[tex]2{x}^{ 2}-7x+1[/tex]
The sum of two trinomials is always a trinomial is a false statement.
Question 2b)
We add the two trinomials to get,
[tex]3{x}^{ 2}-7[/tex]
This is a binomial.
The given function is:
[tex]5 {x}^{4} - 8[/tex]
By number of terms we classify this as a binomial.
By degree, we classify this as a quartic polynomial.
QUESTION 1b)
The given function is:
[tex]4 {a}^{2} - 2a - 16[/tex]
based on number of terms: trinomial
based on degree: quadratic polynomial.
QUESTION 1c
The given function is;
[tex]9 {m}^{3} [/tex]
Using number of terms: monomial
Using degree: cubic polynomial
QUESTION 2a.
Michael's weight:
[tex]72 {x}^{5} [/tex]
Al's weight:
[tex]9 {x}^{7} [/tex]
Ratio:
[tex]72 {x}^{5}:9 {x}^{7} [/tex]
QUESTION 1d
We need to simplify the ratio:
[tex]72 {x}^{5}:9 {x}^{7}[/tex]
We divide both terms in the ratio by;
[tex]9 {x}^{5} [/tex]
This gives us:
[tex]8:{x}^{2}[/tex]
QUESTION 1e
If the ratios were negative, then the ratio becomes:
[tex]72 {x}^{ - 5}:9 {x}^{ - 7} [/tex]
We divide each term of the ratio by,
[tex]9 {x}^{ - 7} [/tex]
This gives us;
[tex]8{x}^{ 2}:1[/tex]
Yes,that will change the answer.
QUESTION 2a
The given trinomials are;
[tex]{x}^{ 2}+7x-8[/tex]
and
[tex]2{x}^{ 2}-7x+1[/tex]
The sum of two trinomials is always a trinomial is a false statement.
Question 2b)
We add the two trinomials to get,
[tex]3{x}^{ 2}-7[/tex]
This is a binomial.