Question

Write in vertex form the quadratic that has a vertex of (3,4)
$y = a(x-h)^{2} + k$
a = 1

h = ?
k = ?

Answer 1

Answer: $h=3\\k=4$

Step-by-step explanation:

By definition, we know that the quadratic equation in the vertex form is:

$y=a(x-h)^{2}+k$

Where (h, k) is the vertex.

We have the vertice. (3, 4)

Then, if the vertex is (3,4), the equation sought is the following:

$y = (x-3) ^ 2 + 4$

Therefore the answer is:

$h=3\\k=4$

Answer 2

Answer:

y =  (x-3)²+4

h  = 3 and k = 4

Step-by-step explanation:

We have given a vertex of a equation.

vertex  = (h,k)  = (3,4)

a = 1

We have to find the quadratic in vertex form.

The quadratic equation in vertex form is:

y = a(x-h)²+k where (h,k) is vertex.

Putting given values in above formula, we have

y = 1(x-3)²+4

y =  (x-3)²+4  is the quadratic equation in vertex form where (3,4) is vertex.

Here h = 3 and k = 4.