Question

Given the following quadratic equation $y = (x-3)^{2} + 9$
What would be the vertex (h,k)?

Vetex = (_,_)

Answer 1

Answer:

Vertex = (3, 9)

Step-by-step explanation:

The vertex form of a quadratic equation y = a(x - h)^2 + k

Now let's compare the vertex form with the given equation and find the vertex = (h, k)

Vertex = (3, 9)

THank you.

Answer 2

Answer: $h=3\\k=9$

Step-by-step explanation:

By definition, we know that the quadratic equation in the vertex form is:

$y=a(x-h)^{2}+k$

Where (h, k) is the vertex.

We have the equation given in the problem:

$y=(x-3)^{2}+9$

Therefore, you can conclude that the vertex is (3,9).

Therefore the answer is:

$h=3\\k=9$