[ Answer ]
[tex]\boxed{-4c \ + \ 15}[/tex]
[ Explanation ]
3(4c + 1) - 4(4c - 3)
[Expand] 3(4c + 1): 12c + 13
12c + 13 - 4(4c - 3)
[Expand] -4(4c - 3): -16c + 12
12c + 13 - 16c + 12
[Simplify] 13c + 13 - 16c + 12: -4c + 15
= -4c + 15
[tex]\boxed{[ \ Eclipsed \ ]}[/tex]
To simplify any expression, add/subtract variables with same variable and constant with constant number.
After simplification, We get, -4c + 15
Given that, 3 ( 4 c + 1 ) − 4 ( 4 c − 3 )
Now open brackets.
[tex]=12c+3-16c+12[/tex]
[tex]=12c-16c+3+12\\\\=-4c+15[/tex]
Thus, after simplification We get, [tex](-4c+15)[/tex]
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